5t^2-100t-1995=0

Solution for 5t^2-100t-1995=0 equation:

5t^2-100t-1995=0

a = 5; b = -100; c = -1995;
Δ = b2-4ac
Δ = -1002-4·5·(-1995)
Δ = 49900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{49900}=\sqrt{100*499}=\sqrt{100}*\sqrt{499}=10\sqrt{499}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-10\sqrt{499}}{2*5}=\frac{100-10\sqrt{499}}{10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+10\sqrt{499}}{2*5}=\frac{100+10\sqrt{499}}{10}
$